Question

Find acceleration if 1) v= 4t^5 +3t^3 +2t 2)v=6t^3 -4 3)v=5t +7t^2 -3t^3 4)v=5t^-3 +2t^-2 -3t^-1

Answer 1

Explanation:

1. differentiating on both the sides of the given question w.r.t. t,

dv/dt = 20t + 9t + 2

a = 29t+2

2. As done in 1 differentiating w.r.t.x to t, on both side,

dv/dt= 18t-4

a= 18t-4

3. Differentiating with respect to t on both the side,

dv/dt = 5 - 14t -9t

a = 5 - 23t

4. As done in the cases above

differentiating w.r.t. t on both side,

dv/dt= 15t +4t+3t

a= 22t