Question

Find Acceleration in each of the Following cases (i) Force = 4 N, Mass = 4kg (ii) Force = 8 N, Mass = 4kg (iii) Force = 18 N, Mass = 6kg

Answer 1

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$\green{ \bf Case \: (i)}$

$\underline{\purple { \bf Given}}$

• Force (F) = 4 N
• Mass = 4 kg

$\underline{\purple { \bf To \: Find}}$

• Acceleration

Formula Used :- $\boxed {\red {\sf \bold {F = m \times a}}}$

Substituting Values

$\longrightarrow \sf 4 = 4 \times a$

$\longrightarrow \sf 4 = 4a$

$\longrightarrow \sf a = \cancel{\dfrac{4}{4} }$

$\longrightarrow \sf a = 1$

Thus, here acceleration is 1 m/s²

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$\green{ \bf Case \: (ii)}$

$\underline{\purple { \bf Given}}$

• Force (F) = 8 N
• Mass = 4 kg

$\underline{\purple { \bf To \: Find}}$

• Acceleration

Formula Used :- $\boxed {\red {\sf \bold {F = m \times a}}}$

Substituting Values

$\longrightarrow \sf 8 = 4 \times a$

$\longrightarrow \sf 8 = 4a$

$\longrightarrow \sf a = \cancel{ \dfrac{8}{4} }$

$\longrightarrow \sf a = 2$

Thus, here acceleration is 2 m/s²

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$\green{ \bf Case \: (iii)}$

$\underline{\purple { \bf Given}}$

• Force (F) = 18 N
• Mass = 6 kg

$\underline{\purple { \bf To \: Find}}$

• Acceleration

Formula Used :- $\boxed {\red {\sf \bold {F = m \times a}}}$

Substituting Values

$\longrightarrow \sf 18 = 6 \times a$

$\longrightarrow \sf 18 = 6a$

$\longrightarrow \sf a = \cancel{\dfrac{18}{6} }$

$\longrightarrow \sf a = 3$

Thus, here acceleration is 3 m/s²

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⠀⠀⠀⠀⠀⠀⠀$\bf Case \: (i) = 1 m/s^{2}$

⠀⠀⠀⠀⠀⠀⠀$\bf Case \: (ii) = 2 m/s^{2}$

⠀⠀⠀⠀⠀⠀⠀$\bf Case \: (iii) = 3 m/s^{2}$

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Answer 2

GIVEN:

• Force = 4N, 8kg and 18N
• Mass = 4kg, 4kg and 6kg

TO FIND:

• What is the acceleration in all the cases ?

SOLUTION:

Let the acceleration in each case be 'a' m/s²

CASE:- ❶

• Force = 4N
• Mass = 4kg

To find the acceleration, we use the formula:-

❰ F = mass $\times$ acceleration ❱

According to question:-

➙ 4 = 4 $\times$ a

➙ 4 = 4a

➙ $\sf{\cancel\dfrac{4}{4}}$ = a

❮ 1 m/s² = a ❯

CASE:- ❷

• Force = 8N
• Mass = 4kg

According to question:-

➙ 8 = 4 $\times$ a

➙ 8 = 4a

➙ $\sf{\cancel\dfrac{8}{4}}$ = a

❮ 2 m/s² = a ❯

CASE:- ❸

• Force = 18N
• Mass = 6kg

According to question:-

➙ 18 = 6 $\times$ a

➙ 18 = 6a

➙ $\sf{\cancel\dfrac{18}{6}}$ = a

❮ 3 m/s² = a ❯

❝ Hence, the acceleration in all cases is 1 m/s², 2m/s² and 3m/s² ❞

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