Find acceleration of a bus traveling a distance of 10m in 10s from rest. (1 Point) () 0.5 −2(a) 0.5 ms−2 () 0.2 −2(b) 0.2 ms−2 () 2 −2(c) 2 ms−2
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Answer:
0.1 m / s
Explanation:
initial velocity ( u ) = 0
distance ( S ) = 10 m
time ( t ) = 10 s
final velocity ( v ) = distance / time
= 10 m / 10 s
= 1 m / s
v = u + at
=> 1 m / s = 0 + a × 10 s
=> 1 m / s = a × 10 s
=> a = 1 m / 10 s
=> a = 0.1 m / s
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