Question

find acceleration of block Mo and normal force applied by surface ...
please do it step by step by making fbd ....and then making equations sperately ...​

Answer 1

Answer:

from Newton's second law ...

F=ma

now ...m=3 kg

and F=mg sin37°-30 cos37°

=(3×9.8)sin 37°-30(cos37°)

=17.693-23.959=-6.266N

now ... acceleration {a}=-6.266/3 m/sec^2

=-2.09m/s^2

the block will accelerate in the direction opposite to the inclination...with a acceleration of 2.09m/s^2

Answer 2

Ma=mgsinθ-30cosθ

a=30*3/5-30*4/5

a=24-18=6m/s in upward direction

n=mgcos30

N=30*4/5=24N