Question

find acceleration that result win 12 Newton net force is applied to 3 kg object and then to 6 kg object​

Answer 1

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Case 1 :5 m/s²

Case 2 :2.5 m/s²

Step-by-step explanation:

Case 1 :When a 15N net force is applied to a 3kg object

Mass(m)=3kg

Force(f)=15N

Acceleration (a)=?

F=m×a

15=3×a

a=5 m/s²

Case 2: When a 15N net force is applied to a 6kg object

Mass(m)=6kg

Force(f)=15 N

Acceleration(a)=?

F=m×a

15=6×a

a=2.5m/s²

A 3-kg object experiences an accelerartion of 5m/s².

A 6-kg object experiences an accelerartion

of 2.5m/s².

Hope its helpful.

Answer 2

Answer:

(a) Here, m = 0.1 Kg,

a=g=10m/s

2

Net force, F=ma=1N

This force acts vertically downwards.

(b) When the train is running at a constant velocity, its acceleration =0, No force acts on the stone due to this motion.

Therefore, force on the stone F= weight of stone=mg=0.1×10=1.0N

This force also acts vertically downwards.

(c) When the train is accelerating with 1 m/s

2

,

an additional force F

′

=ma=0.1×1=0.1N acts on the stone in the horizontal direction.

But once the stone is dropped from the train,

F' becomes zero and the net force on the stone is F=mg=0.1\times 10=1.0N, acting vertically downwards.

(d) As the stone is lying on the floor of the train, its acceleration is the same as that of the train.

force acting on stone, F=ma=0.1×1=0.1N

This force is along the horizontal direction of motion of the train.

Note that in each case, the weight of the stone is being balanced by the normal reaction.