Question

find acceleration when initial velocity=5m/s and final velocity=10m/s and time=300s​

Answer 1

Answer:

Given that the initial velocity of a car is 5m/s and the final velocity is 10m/s in 5s .

We have to find acceleration of car.

Explanation:

From the given data we have ;

   Initial velocity (u) = 5 m/s

   Final velocity (v) = 10 m/s

   Time (t) = 5 s

Now using first equation of motion :

→ v = u + at

Substituting values,

→ 10 = 5 + a * 5

→ 10 = 5 + 5a

→ 10 - 5 = 5a

→ 5 = 5a

→ a = 5/5

→ a = 1 m/s²

Hence,

Acceleration of car = 1 m/s²

__________________________

_______________________________

Equations of motion :-

   v = u + at

   s = ut + ½ at²

   v² = u² + 2as

Answer 2

Answer:

The acceleration is approximately 0.017 m/s^2.

Explanation:

We're given that:

Initial velocity = 5 m/s

Final velocity = 10 m/s

Time taken = 300 s

The formula for acceleration which we can apply here is:

$a = \frac{\triangle v}{\triangle t}$

Just consider it as:

$a = \frac{Change In Velocity}{ChangeInTime(TimeDuration)}$

Change in velocity = Final velocity - initial velocity = 10 m/s - 5 m/s = 5 m/s

Change in time = The time duration given = 300 s

Plugging in the values, we get:

$a = \frac{5 m/s}{300 s}$

The 'seconds/s' unit becomes squared and 5/300 = 0.0166... which we can round to 0.017. This is our acceleration in m/s^2.

Please like, mark as brainliest, and follow IF I helped you, feel free to ask any questions in the comments!