find acceleration when velocity is , v= 3t^3+2t^2+t+1
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In a velocity-time graph, the slope of the representative line is acceleration of the body,
To find slope simply differentiate the equation given for velocity,
On differentiation, you will get
D(v)/dt = 9t^2 +4t +1
Therefore the equation for acceleration is: 9t^2 + 4t + 1
To find slope simply differentiate the equation given for velocity,
On differentiation, you will get
D(v)/dt = 9t^2 +4t +1
Therefore the equation for acceleration is: 9t^2 + 4t + 1
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