Find ad solve the perimeter ofthe squate whose area is 2500m²
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Area of square is side²
So the side of square is √2500
Side is 50m
And perimeter is 4×side
Hence perimeter of the square is 4×50=200m
So the side of square is √2500
Side is 50m
And perimeter is 4×side
Hence perimeter of the square is 4×50=200m
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Given,
Area=2500 m²
⇒s²=2500 m²
⇒s=50 m
perimeter of a square=4×s
=4×50
=200 m
Area=2500 m²
⇒s²=2500 m²
⇒s=50 m
perimeter of a square=4×s
=4×50
=200 m
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