Question

Find:
al length of a rectangle, if its perimeter 32 cm and width = 5 cm.
breadth of a rectangle, if its perimeter 80 m and length - 24 m.​

Answer 1

I) Find the length of a rectangle, if it's perimeter is 32 cm and width is 5 cm.

Given:

• Perimeter of rectangle = 32 cm
• Width of rectangle = 5 cm

To find:

• Length of rectangle?

Solution: Let the Length of rectangle be l.

As we know that,

★ Perimeter of Rectangle = 2(Length + Breadth) ★

Now,

➟ 2(l + 5) = 32

➟ 2l + 10 = 32

➟ 2l = 32 - 10

➟ 2l = 22

➟ l = 22/2

➟ l = 11

•°• Length of rectangle is 11 cm.

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II) Find Breadth of a rectangle, if its perimeter 80 m and length is 24 m.

Given:

• Perimeter of rectangle = 80 m
• Length of rectangle = 24 m

To find:

• Breadth of rectangle?

Solution: Let Breadth of rectangle be b. And, By using same Formula,

★ Perimeter of Rectangle = 2(Length + Breadth) ★

Now,

➟ 2(24+ b) = 80

➟ 48 + 2b = 80

➟ 2b = 80 - 48

➟ 2b = 32

➟ b = 32/2

➟ b = 16

•°• Breadth of rectangle is 16 m.

Answer 2

Given

1. Perimeter = 32 cm, Width = 5 cm
2. Perimeter = 80 m, Length = 24 m

To Find

1. Length
2. Breadth

Solution

1]

$\large \bf Perimeter = 2(l + b)$

32 = 2(l + 5)

32/2 = (l + 5)

16 = l + 5

16 - 5 = l

11 = l

                                                                                   

2]

$\large \bf Perimeter = 2(l + b)$

80 = 2(24 + b)

80 = 48 + 2b

80 - 48 = 2b

32 = 2b

32/2 = b

16 = b