Question

find all 0's of 2x cube+x square-6x-3 if 2 of it's 0's are -root3,root3.

Answer 1

Answer:

There are only two zeroes in this question.

Step-by-step explanation:

2x^3+x^2-6x+3

=(2x+1)(x^2-3)

Zero of 2x+1 is

2x+1=0

=>x=-1/2

Zero of x^2-3 is

x^2-3=0

=>x=√3