Find all angles if l ||m ; PQ is transversal line
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∠1= 35° [corresponding angle]
∠6= 35° [vertically opposite angle]
∠5= 180°-35°
= 145° [linear angle]
∠7=∠5 [vertically opposite angle]
so, ∠7= 145°
∠3=∠1 [vertically opposite angle]
so, ∠3= 35°
∠2= 180°-∠1 [vertically opposite angle]
∠2= 180°-35°
∠2= 145°
∠4= ∠2 [vertically opposite angle]
∠4= 145°
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