Find all angles in cyclic quadrilateral if A is 2y+4 degree B is 6x-4 degree C is 4y-4 degree and D is 7x+2
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In cyclic quad. sum of opposite angles is 180
so
A+C=180
2y+4×4y-4=180
6y=180
y=30
A=64 C=116
and B+D=180
6x-4+7x+2=180
13x=180+2
x=182/13
x=14
B=80 D=100
so
A+C=180
2y+4×4y-4=180
6y=180
y=30
A=64 C=116
and B+D=180
6x-4+7x+2=180
13x=180+2
x=182/13
x=14
B=80 D=100
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