find all no. of tiles of size 15 cm for covering the floor of a room 9m long and 6m wide.find also the tile required if one of tile cost rupees 4.50.
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Answered by
2
Hey mate thank for the question
Hope it helps
Size of tiles =15cm
Size of tiles=15/100=0.15m
Length of room =9m
Breadth of room=6m
Are of room =l×b
Area =9×6
Area of room =54m^2
No of tiles=54/0.15
No of tiles=360
So total cost=360×4.50
Total cost=1620
Answered by
0
Answer:
Length of rectangular floor of room= 9m
breadth of rectangular floor= 6m
∴Area of rectangular floor = length* breadth
= 9*6
= 54 m²
Side of Square tile= 15cmS.
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