Question

Find all pairs of all consecutive odd natural numbers,both of which are greater than 10 that their sum is less than 40​

Answer 1

Step-by-step explanation:

Let the two consecutive odd positive integer be xx and x+2x+2.

Both number are smaller than 10 Therefore

x+2<10

Adding −2−2 to both sides,

x<10−2

⇒x<8

Also sum of the two integers is more than 40.

So,x+x+2>40

⇒2x+2>40

adding −2to both sides,

2x>40−2

⇒2x>38

Divided by 2 both sides

x>19

Then the number greater then 10 and less then 19 are the consecutive odd number pair

In (C) (11,13),(13,15) ,(15,17) ,(17,19) is write answer