Question

find all pairs of consecutive odd positive integers both of which are smaller than 10 such that their sum is more than 11 ​

Answer 1

$\mathtt{\huge{ \fbox{Solution :)}}}$

Let , x be the first odd positive integer and other be x + 2

Given ,

➡The odd positive integers are smaller than 10

Thus ,

x < 10 and x + 2 < 10

x < 10 and x < 8 ----- (i)

And

➡The sum of odd positive integers are more than 11

Thus ,

x + x + 2 > 11

2x > 9

x > 9/2

x > 4.5 ----- (ii)

From eq (i) and (ii) , we get

4.5 < x < 8

Thus , the all pair of consecutive odd positive integers are (5,7) , (7,9)