Question

Find all pairs of consecutive odd positive integers both of which are smaller than 10 such that their sum is more than 11​

Answer 1

Given:

• Positive Integers 10 such that their sum is more than 11.

To be Find:

• Find all pairs of consecutive odd positive integers?

Solution:

Let assume the smaller of the two consecutive odd positive integers be x

∴ Other integer is = x + 2

According to Question, both the integers are smaller than 10

∴ x + 2 < 10

$\implies$ x < 8 ____(i)

According to Question, Sum off two integers is more than 11

∴ x + (x + 2) > 11

$\implies$ 2x + 2 > 11

$\implies$ x > 9/2

$\implies$ x > 4.5 ____(ii)

Thus, From (i) and (ii);

We have x is an odd integer and it can take values 5 and 7

Hence,

• Possible pairs are (5, 7) and (7, 9).