Math, asked by aasskhan94, 1 month ago

Find all positive integers less than 500 which leave remainders 2,4,8 when divided by 9,10,11 respectively

Answers

Answered by avabooleav

0

Answer:

Step-by-step explanation:

L.C.M of 4,5,8,9=360

The difference of divisor and remainder in each case is 1.

Therefore, the required number =360−1=359.

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