Question

Find all positive integers when divide by 3 leavs reminder 2

Answer 1

Answer:

Step-by-step explanation:

All the positive integers when divided by 3 leaves remainder 2

By Euclid’s division lemma

a = bq + r, 0 ≤ r ≤ b

a = 3q + r where 0 < q < 3

a leaves remainder 2 when divided by 3

∴ The positive integers are 2, 5, 8, 11,…

Answer 2

Step-by-step explanation:

Let x be the number which when divided by 3 leaves remainder 2, and y be the quotient,

=> x/3 = y+2

Therefore its equation becomes,

positive integers when divided by 3 leaves 2 = A+2

Where, A = {x : x ∈ All numbers divisible by 3, i.e 3,6,9,12,...}

I hope it helps...