Question

Find all positive integers, when divided by 3 leaves remainder s.​

Answer 1

Answer:

All the positive integers when divided by 3 leaves remainder 2

a = bq + r, 0 ≤ r ≤ b

a = 3q + r

where 0 < q < 3 a

leaves remainder 2 when divided by 3

∴ The positive integers are 2, 5, 8, 11

Answer 2

The question is incomplete

The full question is " Find all positive integers, when divided by 3 leaves remainder 5,,

Solution:

let, x be the Find all positive integers, when divided by 3 leaves remainder 5.

n be the all positive integers.

so, n = 1, 2, 3, 4, .. ..

now, for finding all positive integers, when divided by 3 leaves remainder 5.

we need is equation

x = 3n +5

for n= 1

x = 3*1+5 = 8

for n=2

x = 3*2 +5 = 11

for n= 3

x= 3*3+5 = 14

for n= 4

x = 3*4+5 =17

and so on..

therefore, all positive integers, when divided by 3 leaves remainder 5 are 8, 11, 14, 17, .. .. so on.