Question

find all positive integers, when dividing by 3 leaves remainder 2​

Answer 1

The answer for the all positive integers is 11

Answer 2

Answer:

$a_n=3n+2$

Step-by-step explanation:

We need to find all positive integer which gives 2 as a remainder when divide by 3.

if we divide 5 by 3 then it gives remainder 2

similarly number 8 also gives remainder 2 when divide by 3 and soon..

In general we write this as $a_n=3n+2$ where n is a positive integer.  

By putting all positive integer in $a_n=3n+2$, we get the all positive integer which gives 2 as a remainder when divide by 3.

therefore, solution is $a_n=3n+2$