Find all possible pairs of consecutive ever positive integers such that each of them is greater than 15 and their sum is less than 49
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Answer:
(16,18),(18,20),(20,22),(22,24)
Step-by-step explanation:
the number pairs are consecutive even positive
integers such that each of them greater than 15 and their sum is less than 49
16+18=34
18+20=38
20+22=42
22+24=46
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