Question

find all possible value for y for which the number 32yl is divisible by three . find each such number

Answer 1

Answer:

(y= 3,y=6, y=9)

the numbers are 5331,5361, 5391

Answer 2

Law of divisibility by 3 is sum of digits should be divisible by 3.

3+2+y+1=9+y

So y should be a multiple of 3 .

Possible values of y

y = 0 , 3 , 6 , 9

Such numbers

3201 , 3231 , 3263 , 3293