Question

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find all possible values of a when the distance between (ii) (a,-1)and (5,3)is 5 units
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Answer 1

solution:-

Given AB= 5 Units

Therefore, (AB)² = 25 units

(5-a)² + {3 - (-1)}² = 25

(5-a)² + (3+1)². =25

(5-a)² + 16. = 25

(5-a)². = 25 - 16

(5-a)². =9

(5-a). = ± √9

5 - a =±3

5 - a = 3. or. 5 - a= -3

Therefore ,

a= 2. or 8