Question

find all possible values of x for which the 4 digit number 3 20 X is divisible by 3 also find the numbers

Answer 1

For number divisible by 3, the sum of all its digit must be a multiple of three

ATQ

320X=3n

n={1,2,3......}; X<=9

i.e 3+2+0+X=3n

X=3n -5

n=2 X=1

n=3 X=4

n=4 X=7

Hence values of X={1,4,7}

numbers are= 3201,3204,3207

Answer 2

Answer:

$22235 |2 | \sqrt[2 \sqrt{3 { \div }^{2} } ]{?} | |$