Question

find all possible values of y for which the number 53y1 is divisible by 3 also find each such number​

Answer 1

Answer:

test divisibility by 3= sum of all digit if the sum is divisible by 3 then the whole number is divisible by 3

now we start the answer,

sum of all digits = 5+4+y+1

sum of all digits = 9+y

if we put y = 0 it became 9 that is divisible by 3

if we put y = 3 it became 12 that is divisible by 3

if we put y = 6 it became 15 that is divisible by 3

if we put y = 9 it became 18 that is divisible by 3

so y = 0,3,6,9