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Find all rational zeros of P(x) = x3 - 7x + 6.

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Answered by Itz2minback
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Answer:

Find all rational zeros of P(x) = x3 - 7x + 6.

• 1 Answers. #1. Solve for x: x^3-7 x+6 = 0. The left hand side factors into a product with three terms: (x-2) (x-1) (x+3) = 0. Split into three = equations: x-2 = 0 or x-1 = 0 or x+3 = 0. Add 2 to both sides: x = 2 or x-1 = 0 or x+3 = 0. Add 1 to both sides: x = 2 or x = 1 or x+3 = 0. Subtract 3 from both sides:

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