Find all real values of such that 25|x|=x²+144 a) 4 b) 3 c) 2 d) None
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For x≥0, |x|=x
So, x²-25x+144=0
(x-16)(x-9)=0 ⇔ x=16 or x=9
For x<0, |x|=-x
So, x²+25x+144=0
(x+16)(x+9)=0 ⇔ x=-16 or x=-9
So, there are four zeroes in total.
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