Question

Find all real values of x which satisfy x2-3x + 2 > 0 and x2-3x -4<=0.​

Answer 1

Answer:

x^2-3x+2>0

x^2-2x-x+2>0

x(x-2)-1(x-2)>0

(x-1)(x-2)>0

x-1>0,x-2>0

x>0,x>2

and

x^2+4x-x-4<=0

x(x+4)-1(x+4)<=0

(x-1)(x+4)<=0

x-1<=0,x+4<=0

x=1,x<=-4