English, asked by Anonymous, 10 months ago

find all roots of equation x^11-x^7+x^4-1=0​
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Answered by bhanuprakashreddy23
3

Answer:

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Answered by chantibrahmaiah7
0

x = 1

x= 0.0000 - 1.0000 i

x= 0.0000 + 1.0000 i

x = -1

Step by step solution :

Step 1 :

Checking for a perfect cube :

1.1 x11-x7+x4-1 is not a perfect cube

Trying to factor by pulling out :

1.2 Factoring: x11-x7+x4-1

Thoughtfully split the expression at hand into groups, each group having two terms :

Group 1: x4-1

Group 2: x11-x7

Pull out from each group separately :

Group 1: (x4-1) • (1)

Group 2: (x4-1) • (x7)

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Add up the two groups :

(x4-1) • (x7+1)

Which is the desired factorization

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