Math, asked by makenzie0419, 1 year ago

Find all solutions of sinx-(√1-3sin²x)=0

Answers

Answered by ParamanandaDas
0

 {( \sin(x) )}^{2}  \:  = 1  -  3 {( \sin(x) )}^{2}  \\  =  > 4 { (\sin(x)) }^{2}  \:  = 1 \\  =  >  \sin(x )  =  + (1 \div 2) \: or \:  - (1 \div 2) \\  =  > x = (\pi \div 6) \:  \: or \:  \: ( - \pi \div 6)
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