Question

Find all solutions to the equation 4x^2 + 48x = 81

If you find more than one, then list the values separated by commas. If the solutions are not real, write them in a + bi form.

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

The real solutions to the equation 4$x^{2}$ + 48x = 81.

Step-by-step explanation:

From the above question,

They have given :

The equation 4$x^{2}$  + 48x = 81 can be rearranged to standard quadratic form by subtracting 81 from both sides:

            4$x^{2}$  + 48x - 81 = 0

This equation can be solved using the quadratic formula:

            x = (-b ± √($b^{2}$ - 4ac)) / 2a

            where a = 4,

                       b = 48, and

                       c = -81.

Substituting these values into the formula gives:

            x = (-48 ± √($48^{2}$ - 4 * 4 * -81)) / 2 * 4

            x = (-48 ± √(2304 + 1296)) / 8

            x = (-48 ± √(3600)) / 8

            x = (-48 ± 60) / 8

So, the two solutions are:

x = (48 ± 60) / 8 = 6, -9

These are the real solutions to the equation 4$x^{2}$ + 48x = 81.

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