find all th zeroes of the polynomial 2x4+7x3
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Answer:
p(x)=2x
4
+7x
3
−19x
2
−14x+30
Two of its zeroes are
2
&−
2
so,g(x)=(x−
2
)(x+
2
)⇒x
2
−2
divisor=x
2
−2
Quotient=2x
2
+7x−15
Remainder=0
q(x)=−2x
2
+7x−15
2x
2
+10x−3x−15=0
2x(x+5)−3(x+5)=0
(2x−3)(x+5)=0
2x−3=0
2x=3
x=
2
3
x+5=0
x=−5
so,rootsofequationis
2
,−
2
,
2
3
&−5
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