Math, asked by mukundtripathi93, 6 months ago

find all that zeroes of x^4 +3x^3-20x^2-6x+36,√2and-√2

Answers

Answered by daku1948
1

Answer:

(x) =x4+3x3-20x2-6x+36

x+√2 and x-√2 are the factors of p(x)

then (x+√2)(x-√2) = x2- 2 is also the factor of p(x) on dividing p(x) by x2-2 we get x2+3x-18 as quotient then we factorise it and get (x-3)(x+6)=+3,-6

Answered by Anonymous
4

Answer:

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