find all the angle of Parallalogram ABCD
in which angleA = 3 angle b
Answers
Answered by
0
Answer:
Let ∠B=x
∠A=3∠B=3x
AD∣∣BC
∠A+∠B=180
o
3x+x=180
o
⇒4x=180
o
⇒x=45
o
∠B=45
o
∠A=3x=3×45=135
o
And ∠B=∠D=45
o
Opposite angles of parallelogram are equal
∠A=∠C=135
o
Opposite sides of parallelogram are equal.
AB=CD
5x−7=3x+1
⇒5x−3x=1+7
⇒2x=8
⇒x=4
CD=3×4+1=13
Hence 135
o
,45
o
,135
o
and 45
o
.
Similar questions