Question

Find all the angles of a cyclic quadrilateral ABCD where <A=3y-5, <B=-7x+5, <C=-4x, <D=3y-5.​

Answer 1

Answer:

3y-5 = -4x

4x+3y = 5

-7x+5 = 3y-5

7x+3y = 10

-3x = -5

x = 5/3

20/3+3y = 5

3y = 5-20/3

3y = 15-20/3

3y = -5/3

y = -5/3÷3

y = -5/3×1/3

y = -5/9