find all the angles of a parallelogram if one angle is 12* less than twice of the smallest angle
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124 is the another angle
mistygupta3:
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let the smallest angle be x
other angle =2 x -12
x + 2x -12 +x + 2x -12 = 360
6x -24 = 360
6x = 360 +24
x = 64
smallest angle = 64
other angle = 2x -12 = 116
as we know the opposite angles of a parallelogram are equals so angles are 64...116...64...116. :)
other angle =2 x -12
x + 2x -12 +x + 2x -12 = 360
6x -24 = 360
6x = 360 +24
x = 64
smallest angle = 64
other angle = 2x -12 = 116
as we know the opposite angles of a parallelogram are equals so angles are 64...116...64...116. :)
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