Question

Find all the angles of a parallelogram if one angle is 18° more than twice the sm smaller angle .

Answer 1

$\boxed{\large{\blue{\mathbb{QUESTION}}}}$

Find all the angles of a parallelogram if one angle is 18° more than twice the smaller angle.

$\boxed{\large{\blue{\mathbb{SOLUTION}}}}$

Let,

smaller angle of parallelogram= x

then

larger angle of parallelogram= 2 x + 18°

∵ opposite angles of parallelogram are equal

∴ angles of parallelogram will be

  x , 2 x + 18° , x , 2 x + 18°

Now,

∵ sum of all angles of || gm = 360°

∴ x + 2 x + 18° + x + 2 x + 18° = 360°

6 x + 36° = 360°

6 x = 360° - 36°

6 x = 324

x = 324 / 6

x = 54°

hence,

2 x + 18° = 2(54°) + 18°= 126°

So all angles of parallelogram will be

54° , 126° , 54° , 126° .