Find all the angles of a parallelogram if one angle is 67^o
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Answer:
∠A = 67°
∠B = 113°.
∠C = 67°
∠D = 113°.
Step-by-step explanation:
Let there be a parallelogram ABCD, in which ∠A = 67°.
In a parallelogram, opposite angles are equal.
⇒∠C = 67°.
⇒∠B and ∠D are equal.
Let ∠B =∠D=x.
A parallelogram is a quadrilateral, and the sum of its angles will be 360°.
⇒ ∠A +∠B +∠C +∠D = 360°
⇒ 67° + x + 67° + x = 360°
⇒ 2x = 226
⇒ x = 113
⇒ ∠B = ∠D = 113°.
Adding all angles,
113 + 67 + 113 + 67 = 360.
Therefore, our answer is verified.
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