Math, asked by luckkey3257, 3 days ago

Find all the angles of a parallelogram if one angle is 67^o

Answers

Answered by Agent0009
0

Answer:

∠A = 67°

∠B = 113°.

∠C = 67°

∠D = 113°.

Step-by-step explanation:

Let there be a parallelogram ABCD, in which ∠A = 67°.

In a parallelogram, opposite angles are equal.

⇒∠C = 67°.

⇒∠B and ∠D are equal.

Let ∠B =∠D=x.

A parallelogram is a quadrilateral, and the sum of its angles will be 360°.

⇒ ∠A +∠B +∠C +∠D = 360°

⇒ 67° + x + 67° + x = 360°

⇒ 2x = 226

⇒ x = 113

⇒ ∠B = ∠D = 113°.

Adding all angles,

113 + 67 + 113 + 67 = 360.

Therefore, our answer is verified.

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