Question

Find all the angles of the triangle ABC.​

Answer 1

Answer:

Angle ACB (Angle C) = 80°.

Angle BAC (Angle A) = 35°.

Angle ABC (Angle A) = 65°.

Step-by-step explanation:

Angle ACB + Angle ACD = 180° (Linear Pairs)

=> Angle ACB + 100° = 180°

Thus, Angle ACB = 180° - 100° = 80°.

.

Here, Angle PAQ = Angle BAC (Vertically Opposite Angles)

Thus, Angle BAC = 35°.

.

Finally, In ∆ABC:-

Angle ACB + Angle BAC + Angle ABC = 180° (Angle Sum Property Of Triangle)

=> 80° + 35° + Angle ABC = 180°

=> 115° + Angle ABC = 180°

Thus, Angle ABC = 180° - 115° = 65°.