Question

Find all the angles of triangle ABC

Given,
Angle AOB = 120 degree
Angle BOC = 110 degree


please tell me the answer​

Answer 1

Answer:

Angle AOC = 130

Step-by-step explanation:

Because a circle is of 360 degree.

Answer 2

Step-by-step explanation:

<COB + <BOA + <AOC = 360

(because angles around a point us 360 degrees)

120 + 110 + <AOC = 360

<AOC = 360 -120 -110

<AOC = 130 Degrees

<OAB + OBA + AOB = 180

(Angle sum property of triangles )

120 + <OAB + <OBA = 180

120 + <OAB +<OAB = 180 (<OAB = <OBA = RADIUS OF CIRCLE, isosceles triangle)

120 + 2<OAB= 180

60 + <OAB = 90 (dividing by 2)

<OAB = 90 - 60 = 30 Degree

so, <OBA = 30 Degree.

Similarly,

<OAC = <OCA = 25 Degree

<OBC = <OCB = 35 Degree

Now;

<CBA = <OBC + <OBA = 35 + 30 = 65 Degrees

<CAB = <OAC + <OAB = 25 + 30 = 55 Degrees

<ACB = <OCA + <OCB = 25 + 35 = 60 Degrees

Verification,

<CAB + <ACB + <CBA = 55 + 60 + 65 = 180 Degrees