Question

find all the integral zeros of x^3-3x^2-2x+6

Answer 1

x^3-3x^2-2x+6
x^2(x-3) -2(x-3)=0
(x^2-2) (x-3)=0
x = 3,√2,-√2

Answer 2

Answer:

The integral zeroes of given polynomial is 3

Step-by-step explanation:

Given the polynomial

$x^3-3x^2-2x+6$

we have to find all the integral zeros of the above polynomial.

$x^3-3x^2-2x+6$

$x^2(x-3)-2(x-3)$

$(x^2-2)(x-3)$

$\text{The zeroes of the above polynomial are }3,\sqrt2,-\sqrt2$

Hence, the integral zeroes of given polynomial is 3