Question

find all the natural numbers from 200-401 that are divisible by 5 10th std Arithmetic progression lesson​

Answer 1

Answer:

200 ; 205 ;210;215;220;225;230;235 ;240; 245; 250 ;255 ; 260;265;270;275;280;285

;290;295;300;305;310;315;320;325;330;335;340;345;350;355;360;365;370;375;380;385;390,400

Explanation:

this is becoz..only those didits are able to divide by 5 in which the unit digit is 5 or 0........

so it may be help u and mark me as brilliant plzz this is a humble request to you

Answer 2

Explanation:

numbers divisible by 5 in between 200-401=200,205..................400

a=200,d=5,an=400

an=a+(n-1)d

substitute the values

400=200+(n-1)5

(n-1)5=400-200

(n-1)5=200

(n-1)=200/5

(n-1)=40

n=40+1

n=41

So,numbers that are divisible by 5 in between 200 and 401 are 41