Question

find all the pairs of consecutive odd natural numbers both of which are longer than 10 such that their sum is less than​

Answer 1

Answer:

Step-by-step explanation:

Let the smaller odd natural number be x.

Since;the larger integer consecutive odd,

It will be x+2

Give that,

Both integers are larger than 10,

i.e.; x>10

& x+2>10

x>8

Since x>10&x>8

x>10

Also,given that

Sum of the numbers is less than 40

Therefore,x+(x+2)<40

2x+2<40

2x<40-2

2x<38

x<38/2

x<19

Hence,x>10&x<19

Natural number greater than 8 but less than 19 are

11,12,13,14,15,16,17,18

Odd natural numbers are

11,13,15,17

Hence,x=11,13,15,17

I hope that this answer helps you