Find all the positive divisors of 2^ k×3
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Answer: 168
Step-by-step explanation:
All the positive divisors will have a prime factorization comprised of some subset of the prime factors of the number given.
You can have anything between zero to five 2
′
s in the divisor's prime factorization, that is 6 ways to take the prime factor 2, one extra for not taking 2 at all (2 raised to 0).
Using the same logic for the other prime factors, and multiplying the number of possibilities for each:
(5+1)(6+1)(3+1)=168
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