find all the positive integers divided by 3 leave remainder 2
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When the positive integer "n" is divided by 3, the remainder is 2 and when "n" is divided by 5, the remainder is 1. What is the least possible value of "n"? The answer is 11. My question is, if you have very large numbers to work with in this problem, what would be the quickest and easiest way to calculate this quickly? Thank you for your time and attention to my answer.
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