Question

Find all the positive integral values of p for which p2 +16 is a perfect square

Answer 1

p can be 0,because 0+16=16
p can be 3,9+16=25
p=3 ,0 is the answer

Answer 2

Thus, The value of $P$ are $0$ and $3$

Step-by-step explanation:

Given,

$P^{2}+16$ value is a perfect square where $P=$Positive integral value

• For $P=0$,   $0^{2}+16=16=4^{2}$

                                             Where the value is a perfect square.

• For $P=3$,   $3^{2}+16=9+16=25=5^{2}$

                                             Where the value is a perfect square.

There are have only two value where we gets the value of $P^{2}+16$ is a perfect square.

So, The value of $P$ are $0$ and $3$