Find all the possible values of P and Q, if 342PQ is divisible by 15.
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Answer:
P = 0 , Q = 0
P = 1 , Q = 5
P = 3 , Q = 0
P = 4 , Q = 5
P = 6 , Q = 0
P = 7 , Q = 5
P = 9 , Q = 0
Step-by-step explanation:
Try dividing 34200 by 15 ... 34200 is divisible by 15
Meaning that PQ must be divisible by 15 too
Possible combinations :
P = 0 Q = 0
P = 1 Q = 5
P = 3 Q = 0
P = 4 Q = 5
P = 6 Q = 0
P = 7 Q = 5
P = 9 Q = 0
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