Question

Find all the possible values of x and y if the six digit number is divisible by 4 and 9

Answer 1

Answer:

We know that the given number

67y19

is divisible by 9.

And, if a number is divisible by 9 then sum of digits must be a multiple of 9.

i.e., 6+7+y+1+9= multiple of 9

y+23=0,9,18,27…

Here y is a digit, where, y can have values between 0 and 9.

y+23=27 which gives y=4.

Hence, y=4.