Question

Find all the real factores of 1-16x⁴

Answer 1

Step-by-step explanation:

(1)^2- (4x^2)^2

(1-4x^2)(1+4x^2). ......eq(1)

for real factors eq(1) =0

therefore (1-4x^2)(1+4x^2) =0

1-4x^2=0 and 1+4x^2=0

-4x^2=-1 and 4x^2=-1

x^2=1÷4 and x^2=-1÷4

x=√1/4 and x=√-1/4

x=1/2 and -1/2