Question

Find all the roots
j(x) = 32x^10 - 33x^5 + 1
Answer
X= 1
X= 1/2
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Answer 1

Answer:

Let x^5 = t

=> x^10 = t²

The expression now becomes 32t² - 33t + 1

This is a quadratic equation that can be easily solved.

t = ( 33 ± √(1089 - 128))/64

= (33 ± √961)/64 = (33 ± 31)/64

= 64/64 or 2/64

= 1 or 1/32

t = 1^5 or (1/2)^5

Substituting value of ‘t’,

=> x = (t)^1/5, we have :

x = 1 or x = 1/2

Step-by-step explanation: Please mark me as the brainlest